Lesson 4
Here you'll learn how to divide whole numbers.
Here are the vocabulary words used in this Concept.
Dividend the number being divided
Divisor the number doing the dividing
Quotient the answer to a division problem
Remainder the value left over if the divisor does not divide evenly into the dividend
A general concept overvew statement or word problem exercise can be placed in the concept introduction section.
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You have now learned how to add, subtract and multiply. The last whole number operation that we will learn is long-division.
What does “division” actually mean. The best way to understand it is to think of splitting into groups.
We saw that multiplication means to add groups of things together to get a product or total. Therefore division which is splitting a total into groups is the opposite of multiplication.
7 | 2 | ÷ | 9 | = |
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In this problem we are trying to discover how many groups there will be if we split 72 into groups of 9.
72 is the number being divided, it is the dividend. 9 is the number doing the dividing, it is the divisor.
We can complete this problem by thinking of our multiplication facts and working backwards. Ask yourself “What number multiplied by 9 equals 72?”
Think back to your 9 times tables. If you said “8”, you're right!
9 | × | 8 | = | 7 | 2 |
So 72 can be split into 8 groups of 9. Therefore:
7 | 2 | ÷ | 9 | = | 8 |
The answer to a division problem is called the quotient. Quotient is a really old word that means "how many times".
Sometimes, a number won’t divide evenly. When this happens, we have a remainder.
1 | 5 | ÷ | 2 | = | ? |
In this example we aredividing by two. Because fifteen is not an even number there is going to be a number left over. We call that the remainder. If we look at the the nearest possible multiplication solution:
7 | × | 2 | = | 1 | 4 | + | 1 |
We get 14 and their is an extra 1 required to get to fifteen. So when we divide and have a remainder we write it like this:
1 | 5 | ÷ | 2 | = | 7 | r | 1 |
We can use an “r” to show that there is a remainder.
Here is another example with a larger remainder value.
3 | 5 | ÷ | 9 | = | 3 | r | 8 |
How did we get that? We use our 9 times table to see to the closest value to 35.
9 | × | 1 | = | 9 | |
9 | × | 2 | = | 1 | 8 |
9 | × | 3 | = | 2 | 7 |
9 | × | 4 | = | 3 | 6 |
Our dividend number 35 is smaller than 36 so we have to use 3 × 9 = 27.
Then the remainder is the dividend 35 minus 27. The result is 8. So in this problem our remainder is 8.
In this example we can see the remainder must always be a smaller number than the divider.
Larger numbers can be divided by using a division box. This is a tool we can use to organize the problem so we can get an answer.
Lets have a look at dividing a longer number and how to present the problem so we can work it out.We are going to solve:
7 | 9 | 8 | ÷ | 7 | = | ? |
Use this tutorial to learn how to do this step by step.
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Now that we understand the basic long-division method we can look at another example but this time with a remainder because the divider does not go equally into the dividend.
We are also going to make the problem a little longer.
Now we are going to look at a problem with a two-digit divisor. We are also going to increase the size of the dividend to show how you can easily use your new long-division skills to solve a wide range of dividing problems.
1 | 7 | 7 | 8 | 6 | 8 | 4 |
That looks pretty challenging. But getting the answer is just a matter of going step by step.
If you have an Internet connection here are some videos for you to look at that will help you learn long division.
Take the time to complete all the Exercises and use the Practice and Test Interactive tools to make sure division becomes your friend. Learn to enjoy the numbers. They are fun and these exercises let you do it all at your own speed anytime you want.